T=-16t^2+16t+60

Solution for T=-16t^2+16t+60 equation:

=-16T^2+16T+60

We move all terms to the left:

-(-16T^2+16T+60)=0

We get rid of parentheses

16T^2-16T-60=0

a = 16; b = -16; c = -60;
Δ = b2-4ac
Δ = -162-4·16·(-60)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-64}{2*16}=\frac{-48}{32}
=-1+1/2
$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+64}{2*16}=\frac{80}{32}
=2+1/2
$